makefile - Print the prerequisites to a target -


this duplicate of this question, has not been answered, can see.

here goal: able print prerequisites target.

i have kind of solution feels hack me.

say target all, , has prerequisites, in file named makefile-1:

all: foo  all: bar baz

i can use makefile named makefile-2:

all: ifeq ($(show),yes)     echo $^ else     cat $^ endif

this kind of gives me need, when invoked properly:

$ make -f makefile-1 -f makefile-2 cat foo bar baz $ make -s show=yes -f makefile-1 -f makefile-2 foo bar baz

but not sure if prerequisite has recipe in original makefile, or if there better/cleaner way.

an easier way show prerequisites target without building target use -p option (as suggested here) , -q options together, suggested on gnu-make manual page (long name option --print-data-base):

make -qp | grep '^all:'

this print database , select line has target all , prerequisites. if there rule target, @ end of same paragraph (if understanding format of output correctly).

if multiple makefiles used, 1 can specify of them -f option:

make -f makefile-1 -f makefile-2 -qp

this of course collect prerequisites same target makefiles, target cannot have rule specified in more 1 file.


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