php - If statement in my switch program doesn't work. What am I doing wrong? -
this program supposed show dropdown selection user, output of response particular choice using switch statement in php. can't if statement work though. can me please? thank all.
<!doctype html> <html> <head> <title>program 2</title> </head> <body> <form action="<?php $php_self; ?>" method="post"> <select name="pick"> <option value="regular">i regular customer</option> <option value="friend">from friend</option> <option value="television">on television</option> <option value="online">in online search</option> </select> <input type="submit" value="submit form"><br> </form> <?php $choice = $_post['pick']; if($choice($_post['pick']) echo "excellent. love our regular customers!";) { } else { switch($choice) { case 'regular': echo "excellent. love our regular customers!"; break; case 'friend': echo "please thank friend us."; break; case 'television': echo "we glad hear our tv ads working."; break; case 'online': echo "we work hard found on google."; break; } } ?>
you've got lots of random copy/paste errors in code... instead use:
<!doctype html> <html> <head> <title>program 2</title> </head> <body> <form action="" method="post"> <select name="pick"> <option value="regular">i regular customer</option> <option value="friend">from friend</option> <option value="television">on television</option> <option value="online">in online search</option> </select> <input type="submit" value="submit form"><br> </form> <?php if(isset($_post['pick'])) { switch($_post['pick']) { case 'regular': echo "excellent. love our regular customers!"; break; case 'friend': echo "please thank friend us."; break; case 'television': echo "we glad hear our tv ads working."; break; case 'online': echo "we work hard found on google."; break; } } ?> </body> </htm 
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