c++ - Counting the number of even digits in a number? -


i looking calculate numbers in given string c++. code is:

#include <iostream> #include <sstream> #include <string>  using namespace std;  int i(0), c(0), z(0), j(1), n1, x(0); string n;  int main() {     cout << "hello n world!" << endl;     cin >> n; //the number      while (true)     {         if (( n[i] >= '0' && n[i] <= '9'))         {             x++;         }         else break;         i++;     } //counts numbers      cout << "the number has " << x << " digit(s)." << endl;      istringstream convert(n);     if ( !(convert >> n1) )         n1 = 0; //converts string int      while (c < x)     {         if ( n1 % 2 == 0 )         {             z++;         };         n1 = n1 % 10;         c++;      }; //counts numbers (i can feel part wrong, don't know how)      cout << "the number has" << z << " digit(s)." << endl;      return 0; } 

but when use it, when enter 1022, 4 numbers , if enter 696969 gives 0 numbers. do? wrong code?

n1 = n1/10; not %

that should solve basic logic calculate number of numbers. there other errors in code. don't have c++ on machine - can't run it.


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