pointers - How to store array in address C -


basically provided main function:

 #include <stdio.h>  #include <string.h>  #include <strings.h>  #define storage 255       {  int c;  char s[storage];   for(;;) {     (void) printf("n=%d, s=[%s]\n", c = getword(s), s);     if (c == -1)break;     }}

we not change that

and have create function getword() should contain loop reads characters,

store in array in address provided 1 one , should stop whitespace (tab, space, eof)

basically have this:

int getword(char *w)  {   char str[255];             int = 0;                  int charcount = 0;          printf("enter sentence:\n");    gets(str);     /*this provided professor, i'm not sure how use    while (( iochar - getchar()) !=eof);    */     for(i = 0; str[i] != '\0'; i++)           //loop checks tab , spaces         {             if(str[i] != ' ' && str[i] != '\t')             {                 charcount++;             }         }    printf("your string: '%s' contains %d of letters\n", str, charcount);     return 0;}

right output of program is:

 enter sentence:  hey stockoverflow  string: 'hey stockoverflow' contains 16 of letters  n=0, s=[]

so i'm saving string , counting it, i'm not storing should be.
it should display n=16, s=[hey stockoverflow]
actually should display n=3, s=[hey]

any appreciated

this may looking for:

for(i = 0; str[i] != '\0'; i++)           //loop checks tab , spaces {     if(str[i] != ' ' && str[i] != '\t')     {          charcount++;     }     else     {         str[i] = '\0'; // terminate str         break;         // break out of for-loop     } }  printf("your string: '%s' contains %d of letters\n", str, charcount);   strcpy(w, str); // add line copy str w (which s main)  return strlen(w); // return length of result string

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