c# - Loading the same Assembly twice but with different version -

i have 1 assembly called asm.dll.

this assembly has version 1.0.0.0 (set within assemblyinfo.cs)

then need do code modifications in assembly (still asm.dll), advance version 2.0.0.0 , build again.

now, have 2 files named asm.dll differ respect code modifications , version number.

how load these 2 files during runtime?

addendum:

right trying following:

var asm1 = assembly.loadfrom("dir1\asm.dll"); var asm2 = assembly.loadfrom("dir2\asm.dll");  var types1 = asm1.gettypes(); var types2 = asm2.gettypes();  type type1 = types1.first<type>(t => t.name.equals("myclassiwanttoinstantiate")); type type2 = types2.first<type>(t => t.name.equals("myclassiwanttoinstantiate"));  myobject myobject1 = (myobject1)activator.createinstance(type, new object[] { }); myobject myobject2 = (myobject2)activator.createinstance(type, new object[] { }); 

but following behavior:

• the first call activator.createinstance(...) correctly returns requested instance myobject1

• the second call activator.createinstance(...) returns again myobject1 instead of myobject2

• the code compiles , program runs without exception or observable problems, except not myobject2

i aware of this answer , think code used, same, bit newer (correct me, if wrong).

in answer, using activator.createinstance both objects - using whatever registered globally. believe types loaded specific assemblies not enough this.

in answer linked, assemblies loaded using assembly.loadfile rather loadfrom, , createinstance called on assembly instance, rather using static activator.createinstance. have tried this?

var asm1 = assembly.loadfile("dir1\asm.dll"); var asm2 = assembly.loadfile("dir2\asm.dll");  myobject myobject1 = (myobject)asm1.createinstance("myclassiwanttoinstantiate"); myobject myobject2 = (myobject)asm2.createinstance("myclassiwanttoinstantiate");