c - I do not understand this stu[en-11] line of code. How exactly does accessing a structure member work? -

#include<stdio.h> #include<conio.h> struct student {     int enroll;     char name[50]; }stu[2] = {             {11, "rj"},             {12, "ay"}             }; int main() {     int en;     printf("enter enroll: ");     scanf("%d", &en);     if(en==11 || en==12)     {         printf("%s", stu[en-11].name);         printf("\t%d", stu[en-11].enroll);     }     else         printf("wrong");     return 0; } 

stu[2] array of structure should use loop accessing each members of structure, or stu[0].name, stu[1].name, in code below can access members using stu[en-11]. please help. how work?

the correct index stu in case 0 , 1.

so, en value has either 11 or 12 valid access. you'll needing or operator || instead of , operator &&.

change

  if(en==11 && en==12) 

to

 if(en==11 || en==12) 

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coming stu[en-11] part, you've asked, index value has int, , expression en-11 produces int. that's all.