linux - Bash declaring variable with a number inside a for loop -

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• dynamic variable names in bash 6 answers

i can't find answer problem, other people asking use array instead. that's not want. want declare number of variables inside loop same name except index number.

i=0 int in $ints; i=[$i +1]; intf$i=$int; done 

it doesn't work. when run script thinks middle part intf$i=$int command.

without array, need use declare command:

i=0 int in $ints;     i=$((i +1))     declare "intf$i=$int" done 

with array:

intf=() int in $ints;     intf+=( $int ) done