c - Checking array for identical numbers and their value -

as part of program have make, 1 of function need program should check if array has identical numbers same, , if 1 of them bigger/equals given number.

the given number amount of numbers in array

this have far:

int checkarray(int *arr, int num) {     int check = num;     int check2 = num;     int *lor;     int *poi;     int *another;      = arr;     lor = arr;     poi = arr;     int check3 = num;      ( ; num > 1; num--) {          ( ; check3 >= 0; check3--) {              if (*arr == *poi)                 return 0;             poi++;         }         arr++;         poi = another;     }      ( ; check2 > 0; check2--) {          if (*lor >= check)             return 0;         lor++;     }     return 1; } 

i know made many pointers/int function, that's not problem..

the part of checking given value works fine if i'm not mistaken think can ignore part (that's last 'for' loop)

i know should easy reason can't work...

edit:

i'll give example: if array 0 1 2 3 1 function return 0, cause second , last number identical. function return 0 if given number 5, , 1 of numbers bigger or equals 5, example 0 1 2 5 4.

otherwise, function returns 1.

i create new array i'm going save numbers can check if have repeat number in array. have 1 more argument in function know size of array.

#include <stdio.h> #include <stdlib.h>  int checkarray(int *arr, int size, int number){     int i,j;     int *countarray = calloc(size,sizeof(int));     for(i=0;i<size;i++){         if(arr[i]>=number){  //check >= number             free(countarray);             return 0;         }         for(j=0;j<i;j++){ //check repeat number             if(countarray[j]==arr[i]){                 free(countarray);                 return 0;             }         }         countarray[j]=arr[i]; //no repeat number save it.     }      free(countarray);     return -1; //error  }  int main(){   int arr[6] = {0,8,2,3,4,1};   printf("result %d",checkarray(arr,6,5));  } 

i hope can you.

update without new array

int checkarray(int *arr, int size, int number){     int i,j;     for(i=0;i<size;i++){         if(arr[i]>=number){             return 0;         }         for(j=0;j<i;j++){             if(arr[i]==arr[j]){                 return 0;             }         }     }         return -1; //error     }