scala - How to extract the value of a cell from Future[ResultSet]? -

i data in format, example:

id -- 23 

to future[resultset].

the code serve same purpose without using async shown below.

{ var last_seen_time: long = 0     try {       val results: resultset = session.execute(query)       last_seen_time = results.one().getlong(0) * 1000     }     catch {       case e: throwable => println("error occurred in executing query:" +         "possible cause device not started sending data.")     }     println(s"current_time = $current_time")     println(s"message_post_interval = $message_post_interval")     println(s"last_seen_time = $last_seen_time")      if (current_time.tolong - message_post_interval.tolong <= last_seen_time)       true     else       false } 

how perform same action with:

val results: future[resultset] = session.executeasync(query) 

you can extract result using oncomplete callback of future

val result : future[resultset] = ...  result.map {r => r.one().getint(0)} oncomplete {     case success(v) =>         println(s"id = $v")     case failure(e) =>         e.printstacktrace()     } 

or can wait until executed

val fut = result.map {r => r.one().getint(0)} val id = await.result(fut, 10 seconds) id