sockets - Python, wait until network interface is up? -

i have python script opens port , listens on raspberry. added /etc/rc.local , working properly. problem socket not created when process being executed.

s = socket.socket()       s.bind((host_ip,port)) #e.g. host_ip='192.168.1.32' , port=12345 s.listen(5) while true:     c,addr = s.accept()     c.send('ack')     c.close() 

the above code not executed because there no 'eth0' connection available. should do? should loop scan socket status until connection being available? there other more sophisticated solution?

like this:

import urllib2,thread time import sleep import netifaces   class _check:     def __init__(self):         self.uri="http://www.google.com"         self.period = 5         self.status = false         self.ifaces()     def check(self):         try:             answ = urllib2.urlopen(self.uri)             if answ:                 self.status = true                 #now can run awesome code !                 print "okay go take beer"         except exception,e : print e      def timer(self,pass_arg) :         while true :             if   self.status != true :                 self.check()                 sleep(self.period)                 print "running"             elif   self.status == true :                 print "thread ending"                 break     def ifaces(self):         in netifaces.interfaces() :             try:                 print i,netifaces.ifaddresses(i)[2]             except:                 print i, "iface not !"   check = _check() thread.start_new_thread(check.timer,(none,)) 

so answer equal comment answer.