c++ - logic help for smallest/largest value -


i went thru many version of algorithm sort smallest , largest brain fried. book point , searching online haven't helped @ all. i'm having difficulties @ saving last. used 3 in, 10 cm , 5 cm test cases. entering 3 in first, becomes largest, entering 5 cm second becomes smallest , 10 cm becomes smallest again. tried different version on 2 hours, re-wrote entire section. in book programming principles , practices using c++, in review section, before cant find me out.

#include <iostream> #include <vector> #include <algorithm> #include <string> #include <stdlib.h> #include <iomanip>  using namespace std;  int main() {     vector<double>all_meters;      double smallest= 0,print_smallest, largest = 0,print_largest, num = 0;     string unit, s_input, num_s_input, small_unit, large_unit;      while(cin.good()){          cout << "\n\t\t\t\tenter '|' exit.\n\n";         cout << "\t\tnumber compare followed white space , unit:";         cin >> num_s_input;          if(num_s_input.compare("|") == 0 || (s_input.compare("|") == 0)){             double sum = 0;             (double x : all_meters) sum+=x;             cout << "sum: " << setprecision(4) << sum <<  "m\n";             cout << "smallest number: " << print_smallest << small_unit << endl                  << "largest number: " << print_largest << large_unit << endl                  << "total number of values: " << all_meters.size() << endl                  << "all entered numbers converted meters are: \n";             (double = 0; i<all_meters.size(); ++i){                 cout << all_meters[i] << setprecision(2) <<"m ";             }             cout << "\nalright now, goodbye !\n" << endl;             break;             }         else{             cin >> s_input;             num = strtod(num_s_input.c_str(), null);             unit = s_input;              double meter = 0;             if(unit=="cm"){                     meter = num / 100;}              else if(unit=="in"){                     meter = num / 39.370;}              else if(unit=="ft"){                     meter = num / 3.2808;}              else if(unit=="m"){                     meter = num;}              else {                 cout << "\n\tyou entered wrong unit!\t\n";}              if(largest==0){                 largest = meter;                 print_largest = num;                 large_unit = unit;                 cout << num << unit << " largest far.\n";             }             else if(smallest==0&&meter<largest){                 smallest = meter;                 print_smallest = num;                 small_unit = unit;                 cout << num << unit << " smallest far.\n";             }             else if(largest<meter){                 largest = meter;                 print_largest = num;                 large_unit = unit;                 cout << num << unit << " largest far.\n";             }             else if(smallest>meter){                 smallest = meter;                 print_smallest = num;                 small_unit = unit;                 cout << num << unit << " smallest far.\n";             }             all_meters.push_back(meter);             sort(all_meters.begin(),all_meters.end());         }     } }

managed solve without using limit, added new changes code. guys !

you need choose standard unit of measure. question suggests meters, use (you can use float or double this, depending on precision need).

the problem simple, create variables sum, smallest seen, , largest seen, each new input, convert standard format, , update variables.

the solution (to started, not working code) might this:

// can represent different types of units integers float converttometers(float unconvertedvalue, int unit) {   // convert unconvertedvalue based on unit }  float smallest = std::numeric_limits<float>::max(); float largest  = std::numeric_limits<float>::lowest(); float sum      = 0.0f;  // update each new input while (new_input) {   float convertedvalue = converttometers(new_value, unit);    // update total   sum += convertedvalue;    // update smallest , largest   if (convertedvalue > largest) largest = convertedvalue;   else if (convertedvalue < smallest) smallest = convertedvalue; }

as nathan mentioned, #include <limits> limits.


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