python - Add the elements in a row, for each row, in a matrix, using theano -


i have vector v , matrix z, say

v = theano.shared(rng.normal(0, 1, 10)) z = theano.shared(rng.normal(0, 1, (10, 10)))

i want create new vector y given v + sum of elements in each row of z. basically: y[i] = v[i] + t.sum(z[:,i]) can do, each entry, by:

y[i] = v[i] + theano.tensor.sum(z[:][i])

my question is: there way, without doing loop, write y = v + t.sum(rows of z) in 1 single line?

you can obtain this

y = v + z.sum(axis=1)

in numpy, , in theano, many aggregator functions, such sum, mean, var, std, any, all, ... have axis keyword argument, , axes keyword argument, can specify in direction array traversed.


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