printf - assign zero in unsigned short int in c -

i try assign 0 field in structure called list

list.ultimo = 0; 

but when use printf

printf("%d", list.ultimo); 

i result

32766 

but when add

unsigned short int cero = 0; 

the result of printf correct, no matter not use cero. why?

lista.h

#ifndef lista_h #define lista_h  typedef struct{   elemento lista[tamanomax];   unsigned short int ultimo; }lista;  void insertar(elemento, unsigned short int posicion, lista); #endif 

lista.c

#include<stdio.h>  typedef short int elemento; #ifndef tamanomax #define tamanomax 10 #endif #include"lista.h"  void insertar(elemento x, unsigned short int p, lista lista){   if (lista.ultimo >= tamanomax){     puts("full list");     printf("%hu",lista.ultimo);    } } 

main.c

#include<stdio.h>  typedef unsigned short int elemento; #define tamanomax 4 #include"lista.h"  int main(){   lista esferas;   esferas.ultimo = 0;    insertar(2,0,esferas);   printf("\n%hu\n", esferas.ultimo);   return 0;  } 

the result is

$gcc -wall lista.c main.c  full list  32765  0 

i'm new this, i'm slow now, regret delay

use %hd print short int , %hu print unsigned short int. %d int.

edit: have posted full code, appears tamanomax set 10 in lista.c, set 4 in main.c, leading incompatibilty between main() function , insertar one. should have same value in files. , if want work different array lengths, add length member in lista structure. tamanomax should absolutely same everywhere, else you're in fact working different data types , program won't work.