c - static variables and local -

the output : 100 -10 0 100 -5 2 10. why? after running first time b() static x @ end of b() -5 (i check) why c() gave 0, isn't use static x?

#include <stdio.h> extern int x; void a() {     int x=100;     printf("% d ",x);     x+=5; } void b() {     static int x=-10;     printf("%d ",x);     x+=5;  } void c() {      printf("%d ",x);     x+=2; } int main() {     int x=10;     a();     b();     c();     a();     b();     c();     printf("%d ",x);      return 0; } int x=0; 

in

void c() {      printf("%d ",x);     x+=2; } 

it not use static copy of x allocated in defination function b().

it use global copy of variable x have declared in last line of program.

int x=0; 

change last line of x different value , output changed c()

---

why global 1 , not static?

so here in scope of static variable x limited body of b() in c() can not used.

c() depending on global copy of x. if remove global definition of x in c() give compilation error.