searching specefic word in shell script -

i have problem.please give me solution.

i have run command given below, list files contain string given "abcde1234".

find /path/to/dir/ * | xargs grep abcde1234

but here display files contain string "abcde1234567" also.but nee files contain word "abcde1234". modification shall need in command ??

when need that, use \< , \> mean word boundary. this:

grep '\<abcde1234\>'

the symbols \< , \> respectively match empty string @ beginning , end of word. 

but that's me. correct way might use -w switch instead (which tend forget about):

-w, --word-regexp           select    lines  containing matches form whole words.  test matching substring must either @ beginning of line, or preceded non-word constituent character.  similarly,           must either @ end of line or followed non-word constituent character.  word-constituent characters letters, digits, , underscore. 

one more thing: instead of find + xargs can use find -exec. or grep -r:

grep -w -r abcde1234 /path/to/dir/